3x-(x^2-10x+25)=0

Solution for 3x-(x^2-10x+25)=0 equation:

3x-(x^2-10x+25)=0

We get rid of parentheses

-x^2+3x+10x-25=0

We add all the numbers together, and all the variables

-1x^2+13x-25=0

a = -1; b = 13; c = -25;
Δ = b2-4ac
Δ = 132-4·(-1)·(-25)
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{69}}{2*-1}=\frac{-13-\sqrt{69}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{69}}{2*-1}=\frac{-13+\sqrt{69}}{-2}
$